[Tutor] clarification on os.path.walk
Chandrashekar
mailchansek at yahoo.com
Tue Jun 12 08:16:37 CEST 2007
Hi,
I have a program like this.
import os,os.path
import re
def print_files(arg,dir,files):
'''print 'arg', arg
print 'dir', dir
print 'files',files'''
for file in files:
path = os.path.join(dir,file)
path = os.path.normcase(path)
if re.search(r".*\.txt",path):
print path
os.path.walk('.',print_files,1)
My doubt is that what does the argument stand for in this program?
os.path.walk('.',print_files,0)
os.path.walk('.',print_files,1)
os.path.walk('.',print_files,2)
all seems to be rendering the same output. Can anyone clarify when this argument is used.
Thanks,
Chandru
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