[Tutor] Python on Windows: any way to access shortcut's info?
Terry Carroll
carroll at tjc.com
Mon Jan 9 00:19:17 CET 2006
I would like to know the name of the shortcut (link, I think, in Unix
parlance) from which a python program is being invoked. I'd also like to
be able to access the directory where the shortcut lives.
Toy example: here's a directory structure:
C:\
test\
argtest\
arga.py
argb.py
testdir\
argc.py
arga.py contains:
import sys,os
print "ARGS:", sys.argv
print "WD:", os.getcwd()
raw_input() # just to keep the window open
argb.py and argc.py are both shortcuts to arga.py
When I run arga.py (e.g., by double-clicking on it, I get, as expected:
ARGS: ['C:\\test\\argtest\\arga.py']
WD: C:\test\argtest
When I run argb.py, I get the same thing. I'd hoped (but didn't really
expect) sys.argv would be ['C:\\test\\argtest\\argb.py'] .
When I run argc.py, same thing. In this case, I'd hoped sys.argv would be
['C:\\test\\argtest\\testdir\\argc.py']; and os.getcwd() would have given
back 'C:\test\argtest\testdir'.
Why do I care?
Well, I'd like to set up a directory where the shortcut and all its
files will live. I'd hoped keying off of the shortcut name might be an
easy way to do this.
I suspect I'm out of luck: my guess is that windows does all the lookup of
what the shortcut points to, and then launches the file pointed to; and by
the time Python gets control, the shortcut information is long gone.
Anyone know for sure?
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