[Tutor] regExpress

[Eric Walker]

Thanks so much Kent..

Eric ...

--- Kent Johnson <kent37 at tds.net> wrote:

> Eric Walker wrote:
> > All,
> > If I have something like this:
> > import re
> > sample = 'myboss:isbad'
> > express = re.compile('(.*):(.*))
> > answer = re.match(express,sample)
> > 
> > how do I get it to  tell me if it was a match or
> not. I have tried 
> > answer.match . It just gives me an object pointer
> or something.
> 
> re.match() will return None if there is no match, or
> a match object if it succeeds. And your syntax isn't
> quite right, if you compile the re then call match()
> directly on the compiled object. With re.match() you
> pass the re string as the first arg and you don't
> have to compile it. In either case, the methods of
> the match object give details of the match.
> http://docs.python.org/lib/match-objects.html
> 
> Finally, you may want to use re.search() instead of
> match(); match will only match the re at the
> beginning of the string, kind of like if the re
> started with '^'.
> 
>  >>> import re
>  >>> sample = 'myboss:isbad'
>  >>> express = re.compile('(.*):(.*)')
>  >>> answer = express.match(sample)
>  >>> answer
> <_sre.SRE_Match object at 0x008C4A40>
>  >>> answer.groups()
> ('myboss', 'isbad')
>  >>> answer = express.match('No colon here, move
> along')
>  >>> answer
>  >>> print answer
> None
> 
> Kent
> 
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> 



		
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