[Tutor] Newbie in Python (fwd)

[Liam Clarke]

Hi Oscar, 

processing emails... you want to use the email module. 

I believe, you'd go like this (and this is rough, and untested, docs are 
http://docs.python.org/lib/node565.html)

>>>import email
>>>parser = email.HeaderParser() 
>>> msgFile = file('email.txt','r')
>>> msgObj = parser.parse(msgFile)
>>> print msgObj['subject']

Try that out, it should do it for you... might have to tweak it, as I
don't the intepreter here.

Regards, 

Liam Clarke


On Wed, 16 Mar 2005 09:01:05 -0800 (PST), Danny Yoo
<dyoo at hkn.eecs.berkeley.edu> wrote:
> 
> [Forwarding to tutor at python.org.  Oscar, when you reply next time, please
> use your email client's Reply-to-all feature.  Otherwise, no one else will
> see the message.]
> 
> 
> ---------- Forwarded message ----------
> Date: Wed, 16 Mar 2005 23:03:13 +1100
> From: oscar ng <oscar2 at aapt.net.au>
> To: 'Danny Yoo' <dyoo at hkn.eecs.berkeley.edu>
> Subject: RE: [Tutor] Newbie in Python (fwd)
> 
> Hi Danny,
> 
> Thanks for the reference.  I managed to read all the folders and am able
> to open all the files in the directory using a for loop
> Here is the code:
> 
> def getFiles(parent):
>     #used to get the parent directory for the files to process
> 
>       mainFolder = os.listdir(parent)
> 
>       for a in mainFolder:
>           if os.path.isdir(parent + "/" + a):
>               subfolders = [a]          ##set the subfolders to the its
> ##categories
>               print subfolders
>               getFiles(parent + "/" + a)
> 
>           else:
> 
>              fileName = [parent + "/" + a]
> 
>              listFile = a       #listFile is a list that holds the name
> of                                        #files
> 
>              #print listFile,
> 
>              #listFile[a] +=1
>              #print listFile
> 
>              words=[]
>              for b in fileName:
>                 inputFile = open(b)         #inputFile holds the
> #individual/basic files to be
> #processed
>                 listText = inputFile.read() #listText holds entire texts
> of                                                        #all the files
> from parent
> #directory
> 
>                 print listText
> 
> I need now to ask how I can process the headers "subject" of each
> individual email/file as the content of the "subject" determines the
> appropriate category I need to place them into.  As listtext only prints
> all the emails in the folder.
> 
> Also is there a way I can count the number of files ie  listFile[a] +=1
> as this keeps giving errors when running it.
> 
> Thanks heaps
> 
> Oscar
> 
> 
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> http://mail.python.org/mailman/listinfo/tutor
> 


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