[Tutor] What's the invaild syntax? Error message and relative code supplied.
Nathan Pinno
falcon3166 at hotmail.com
Mon Aug 1 01:38:33 CEST 2005
What the invalid syntax? Here is the error message:
SyntaxError: invalid syntax
File "D:/Python22/grades.py", line 66
which = which-1
^
SyntaxError: invalid syntax
Here is the code:
max_points = [25,25,50,25,100]
assignments = ['hw ch 1','hw ch 2','quiz ','hw ch 3','test']
students = {'#Max':max_points}
def print_menu():
print "1. Add student"
print "2. Remove student"
print "3. Print grades"
print "4. Record grade"
print "9. Exit"
def print_all_grades():
print '\t',
for i in range(len(assignments)):
print assignments[1],'\t',
print
keys = students.keys()
keys.sort()
for x in keys:
print x,'\t',
grades = students[x]
print_grades(grades)
def print_grades(grades):
for i in range(len(grades)):
print grades[i],'\t\t',
print
def choice():
return int(raw_input("Menu Choice: "))
def school():
return raw_input("Student: ")
while 1:
print_menu()
menu_choice = choice()
if menu_choice == 1:
print "Add student"
name = school()
students[name] = [0]*len(max_points)
elif menu_choice == 2:
print "Remove student"
name = school()
if students.has_key(name):
del students[name]
else:
print "Student: ",name," not found."
elif menu_choice == 3:
print_all_grades()
elif menu_choice == 4:
print "Record Grade"
name = school()
if students.has_key(name):
grades = students[name]
print "Type in the number of the grade to record"
print "Type in a 0 (zero) to exit"
for i in range(len(assignments)):
print i+1,' ',assignments[i],'\t',
print
print_grades(grades)
which = 1234
while which != -1:
which = int(raw_input("Change which Grade: ")
which = which-1
if 0 <= which < len(grades):
grade = int(raw_input("Grade: ")
grades[which] = grade
elif which != -1:
print "Invalid Grade Number"
else:
print "Student not found"
elif menu_choice == 9:
break
else:
print "That's not a choice!"
print "Goodbye."
Thanks for the help in advance!
Nathan
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