[Tutor] Find out if a number is even or not

[Riumu Kuraku]

I don't quite understand the syntax of

return x % 2 and 'Even' or 'Odd'... 
so if x > 0 it should return x and 'Odd', but if x is 0 then it 
returns 0 and 'Even'?

How does that work?

I can see how your isOdd function works, if x divides by 2 with no
remainder, then isOdd(x) is False.

I'm having trouble understanding conditionals, like... if x:   So if x
is... what exactly? Is it checking for a non-null or non-zero value?
Or if not x:....

Can anyone recommend a link that goes into details on if & while
statements, and the various checks?

Regards,

Liam Clarke

On Fri, 15 Oct 2004 23:51:37 +0100, Alan Gauld <alan.gauld at freenet.co.uk> wrote:
> > >def OddorEven(x):
> > >a=0
> > >a=x % 2
> > >if a ==0:
> > >     return "Even"
> > >else:
> > >     return "Odd"
> 
> I may have missed this one earlier but an obvious shortner
> here is:
> 
> def OddorEven(x):
>    return x % 2 and 'Even' or 'Odd'
> 
> But IMHO better still is to turn it into a true predicate:
> 
> def isOdd(x):
>    return x%2
> 
> So we get a boolean result and can display a suitable message
> outside the function. Keeping presentation away from logic is
> nearly always the right thing...
> 
> Alan G.
> 
> 
> 
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