[Tutor] String matching in 1.5.2 problem
Daniel Nash
dan_nash@hotmail.com
Wed May 7 11:06:01 2003
I have a python 1.5.2 string matching problem.
I have two lists of email addresses:
list1 = ["dan@NO-SPAM.company.com","fred@NO-SPAM.company.com"]
and another list made up from the contents extracted from an email's headers
To:,Cc: & Bcc:
list2 =[('', 'support@NO-SPAM.company.com'), ('jim',
'jim@NO-SPAM.company.com'), ('',
'fred@NO-SPAM.comapny.com')]
I am trying to write a peice of code that will run in python 1.5.2 to return
true if any element in list1 appears in list2.
In python2 I had this and it served its purpose:
for X,Y in list2:
for List1Head in List1:
if Y.find(List1Head) == -1:
# if false then do nothing
print "Is NOT Addressed to: ", List1Head
else:
print "Is Addressed to: ", List1Head
But I have to make it run on 1.5.2 and I get the following message:
Traceback (innermost last):
File "MAILIN.py", line 55, in ?
if Y.find(List1Head) == -1:
AttributeError: 'string' object has no attribute 'find'
Can anyone tell me how to alter my code to work/improve on my code to only
return true on an exact match of an email address rather than a sub string
which allows errors as returning ture for MILE.COM WITHIN SMILE.COM?
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