[Tutor] Using a Stack to evaluate postfix....?
evros
loizie@hotmail.com
Tue Jun 17 23:51:02 2003
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what happen if we have an example with a negative number ex:
((2*3)-10)=3D -4 in postfix will be liek that 23*10- is that =
correct?
if i try to use stack now to evaluate i will have :push 2 then push =
3,then perfom the operation* so we have 6 push 6 then push 10 then pop =
the operand off the stack. my question now are we gona have 10-6 or 6-10 =
. which one is going first?
thanks for teh help
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<DIV><FONT face=3DArial size=3D2>what happen if we have an example with =
a negative=20
number ex:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>((2*3)-10)=3D =
-4 in postfix=20
will be liek that 23*10- is that correct?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>if i try to use stack now to evaluate i =
will have=20
:push 2 then push 3,then perfom the operation* so we have 6 push 6 then =
push 10=20
then pop the operand off the stack. my question now are we gona have =
10-6 or=20
6-10 . which one is going first?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>thanks for teh help</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV></BODY></HTML>
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