[Tutor] Parse Problem [2]

[fleet@teachout.org]

I think I've got it licked.  As I told Danny, I don't control the file
that I'm parsing so splitting on the quotes or including commas etc. is
not an option.  Here's what I've done:

import time
import string

curtime=time.localtime(time.time())
curdate=time.strftime("%y%m%d",curtime)

log=open("log","r")
for rline in log.readlines():
   line=string.split(rline," ")
   if line[1]=="Matched":
      line1=rline[19:-2]              <--  #slicing the "unsplit" line
      print "%s %s" % (line1, curdate)     #that meets the criteria of the
   line=string.split(rline,":")            #'if' statement.
   # note use of continuation below.
   if line[1][1:-1] =="Missing action" or \
                       line[1]=="Invalid regexp" or \
                       line[1]=="Incomplete recipe":
      line1=line[1][1:-1]
      print "%s %s" % (line1, curdate)

				- fleet -

PS: Danny, two minutes after I posted to you with the grep|cut|sed shell
command, I realized it was also including only the first word - and for
exactly the same reason.

On Mon, 12 Aug 2002 alan.gauld@bt.com wrote:

> > Given the strings 'xxxxx: xxxxx "xxx xxx"' and 'xxxxx: xxxxx
>
> > need to get everything within the quotes as xx[2].
>
> A quick guess - why not split on the quotes:
>
> string.split(str, '"') ?? Would that help?
>
> Alan g
>