[Tutor] Dict question

[Daniel Coughlin]

>             if error_dict.has_key(error):
>                 l = error_dict.get(error)
>                 l.append(error_ip)
>                 append = {error: l}
>                 error_dict.update (append)
>             else:
>                 x = [`error_ip`]
>                 append = {error: x}
>                 error_dict.update (append)
>
if error_dict.has_key(error):
	l = []
	l.append(error_dict.get(error))
	l.append(error_ip)

etc.
I've never used the get() before but it appears to return the value associated
with the key, which in this case is a string. You were then assigning that
string to l. In this case we declare l as a list first then append values to it.
That should work for you. (I didnt test it!)

Hope this helps!

Daniel