[Tutor] Word count help
Kalle Svensson
kalle@gnupung.net
Tue, 30 Jan 2001 21:18:44 +0100
--9crTWz/Z+Zyzu20v
Content-Type: text/plain; charset=iso-8859-1
Content-Disposition: inline
Content-Transfer-Encoding: quoted-printable
Hi. Just a minor note...
Sez Jose Amoreira:
> #----------------------------
> def Wordcount(testo,freqs):
> # freqs is a dictionary with words as keys and their frequencies as
> # values; testo is a part of the input file(I'm trying to keep your c=
ode
> # structure, but removed the OO because I didn't understand it
> for word in test.split():
> if word in freqs.keys():
Shouldn't this be
if freqs.has_key(word):
?
IIRC, dict.keys() and if x in list are both linear time. dict.has_key() is
constant time. I repeat, IIRC. <wink> And somebody might have optimized i=
t.
Peace,
Kalle
--=20
Email: kalle@gnupung.net | You can tune a filesystem, but you
Web: http://www.gnupung.net/ | can't tune a fish. -- man tunefs(8)
PGP fingerprint: 0C56 B171 8159 327F 1824 F5DE 74D7 80D7 BF3B B1DD
--9crTWz/Z+Zyzu20v
Content-Type: application/pgp-signature
Content-Disposition: inline
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.0.4 (GNU/Linux)
Comment: For info see http://www.gnupg.org
iD8DBQE6dyGkdNeA1787sd0RAtTrAJ0VkcNebp1jbtyJGOBMflglzMYZRwCffx55
lYOimo1Xvzk9Ilmc/6MSOWQ=
=T9uM
-----END PGP SIGNATURE-----
--9crTWz/Z+Zyzu20v--