[Tutor] square root

[Andrew Wilkins]

There's no operator for squareroot (unless I've been misleading myself
for this long).

Use the power rule of x**(1/y). Here's the relavent rules:

x**y == x to the power of y,
x**(1/y) == x to the root of y,
x**(z/y) == x to the root of y - all raised to the power of z,

So x**(1/2) == the square root of x

I don't think it was a dumb question, but then, I'm a newbie script
kiddie! =)

Andrew Wilkins

> -----Original Message-----
> From: tutor-admin@python.org
> [mailto:tutor-admin@python.org]On Behalf Of
> W.W. van den Broek
> Sent: Thursday, 1 February 2001 5:13
> To: tutor@python.org
> Subject: [Tutor] square root
>
>
> How do you use the
> square root as operator
> in python?
> Dumb question, but
> thanks anyway,
> walter
> --
> W.W. van den Broek
> e-mail:
> vandenbroek@psyd.azr.nl
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