[Tutor] ok, got a primitive but workable solution
Kirk Bailey
deliberatus@my995internet.com
Fri, 28 Dec 2001 17:16:14 -0500
I wanted to trim a statement down to give me ONLY the name of the list.
I got it.
Probably not the best solution, but it works, and works in python 1.5.2
which is what is in my server.
'list' is a string, such as: './lists/testlist3.info'
I want to extract the pure list name so I can display ONLY that. This
works.
def getname(list):
a=string.split(list,'/')
b=a[2]
c=string.split(b,'.')
return c[0]
>>> a
['.', 'lists', 'mylist.info']
>>> list
'./lists/mylist.info'
>>> string.split(list)
['./lists/mylist.info']
>>> string.split(list,'/')
['.', 'lists', 'mylist.info']
>>> def getname:
SyntaxError: invalid syntax
>>> def getname(list):
a=string.split(list,'/')
b=a[2]
c=string.split(b,'.')
return c[0]
>>> list
'./lists/mylist.info'
>>> getname(list)
'mylist'
>>>
--
Respectfully,
-Kirk D Bailey (C)2001
Addme! icq #27840081
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