[Tutor] Need more precise digits

[Lloyd Kvam]

You really want something like:
avgsize = float(totalsize)/float(groups)

In older Python's:
	22/10 = 2
	float(22/10) = float(2) = 2.0

You need to convert to float BEFORE doing the division.


Mike Yuen wrote:

> I've trying to calculate an average and it looks like i'm losing some
> precision in digits.
> 
> For example: i've got the following formula
> avgsize = float(totalsize/groups)
> 
> both totalsize and groups are integers
> I've got 10 groups
> sizes are:
> 2+3+2+2+3+2+2+2+2+2 = 22
> 
> I should get 22/10 = 2.2.
> 
> What I get is 2.0.  How do I get this missing 2 tenths?  As you can see
> from the above, I already casted to a float.
> 
> Thanks,
> M
> 
> 
> 
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> 
> 


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Lloyd Kvam
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