[Tutor] why the error?

[Timothy Wilson]

On Tue, 30 May 2000, Wesley J. Chun wrote:

> well, guess what.  it should *not* have worked in the interpreter either.
> the problem with the code is here:
> 
>     >    for j in range(2, sqrt(number)+1):

Isn't the reason that it worked in the interpreter because I was passing an
integer directly?

>>> isPrime(17)
17 is prime.

> the reason why you get a TypeError is because the sqrt()
> function expects a floating point number.  you passed in
> a string.  the string comes from raw_input():
> 
>     >    number = raw_input("Which number? ")
> 
> the raw_input() built-in function returns a raw string of
> what the user enters.

Of course. That makes complete sense.

> finally, i am not familiar with the "%i" directive for the
> string format operator:
> 
>     >       print "%i is prime." % number
> 
> do you mean "%d" for integer?

I didn't have any python docs handy at the time so I guessed. It works. Go
figure.

> hope this helps!!

Thanks very much.

-Tim

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