[Tkinter-discuss] Stopping a for loop with a sleep() funciton in it

[Cameron Laird]

On Sun, Jul 13, 2008 at 12:23:29PM -0700, Alexnb wrote:
> > 			.
> > 			.
> > 			.
> > Alex, I'm lost as to what your current status is--what
> > you see as solved, and what questions still remain.
> > Do you see why the fragment above is unlikely to make
> > you happy?  after()'s second argument names a function;,
> > it doesn't expect the coder to invoke it.  Does the 
> > self-scheduling in <URL:
> > http://tkinter.unpythonic.net/wiki/after > make sense?
> > How did it not serve you better to write
> > 
> >      root.after(100000000, sleeper)
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> Well Thats what I said, only, it didn't help. It was for a busy bar and the
> bar would stop unless I was using the for loop with the time.sleep() in it.
> However, it would always stop at the same spot with after(), but when I used
> after(100, sleeper()) vs after(100, sleeper) the sleeper() would still stop,
> but it would go a little further down the bar track. If that makes sense.
> But I have given up on the idea for now, but thanks for your attempt to
> help!
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When you write that you "have given up ...", does that
mean that a working busybar would not be a value to you
now?