[SciPy-User] SciPy and Recursion
David Baddeley
david_baddeley at yahoo.com.au
Sat Feb 26 17:32:59 EST 2011
now got scipy running - you're going to want:
dist_list = sp.distance.cdist(cluster_shifted, xyz.reshape((-1, 3)))
you might also want to try removing the recursion from random_on_sphere. (if
nothing else, recursion is slow)
something like:
def random_on_sphere(radius):
x12=s.random.uniform(-1.,1.,2)
while (s.sum(x12**2.)>=1.):
x12=s.random.uniform(-1.,1.,2)
.......
should do the trick
cheers,
David
----- Original Message ----
From: David Baddeley <david_baddeley at yahoo.com.au>
To: Lorenzo Isella <lorenzo.isella at gmail.com>
Sent: Sun, 27 February, 2011 11:10:07 AM
Subject: Re: [SciPy-User] SciPy and Recursion
Hi Lorenzo,
I think the segfault is caused by the python stack overflowing (with all the
function calls) - hence the reason for the limit. Still seems like a bug to me
though.
Looking at your code again, it seems like accept_reject_monomer_pos gets will
still get called recursively most of the time. I'd suggest trying a
non-recursive version of the algorithm, for example:
def accept_reject_monomer_pos(cluster_shifted, dist,epsi):
while(True):
xyz=random_on_sphere(dist)
dist_list=s.hstack([sp.distance.euclidean(xyz,cluster_shifted[i,:]) for
i in range(s.shape(cluster_shifted)[0])]
if (not (dist_list < (2.-epsi)).any()) and (dist_list<=(2.+epsi)).any():
cluster_shifted=s.vstack((cluster_shifted, xyz))
return cluster_shifted
you might be able to make it even simpler/faster by replacing the
'dist_list=s.hstack([sp.distance.euclidean(xyz,cluster_shifted[i,:]) for i in
range(s.shape(cluster_shifted)[0])]' line with:
dist_list = sp.distance.cdist(cluster_shifted.T, xyz)
(I'm not quite sure if the transpose is necessary & don't currently have access
to scipy to check it out)
cheers,
David
----- Original Message ----
From: Lorenzo Isella <lorenzo.isella at gmail.com>
To: david_baddeley at yahoo.com.au
Cc: scipy-user at scipy.org
Sent: Sun, 27 February, 2011 7:43:06 AM
Subject: Re: [SciPy-User] SciPy and Recursion
Hi David and thanks for helping.
> Date: Fri, 25 Feb 2011 10:41:05 -0800 (PST)
> From: David Baddeley<david_baddeley at yahoo.com.au>
> Subject: Re: [SciPy-User] SciPy and Recursion
> To: SciPy Users List<scipy-user at scipy.org>
> Message-ID:<723722.34809.qm at web113408.mail.gq1.yahoo.com>
> Content-Type: text/plain; charset=utf-8
>
> It's a python feature designed to catch infinite recursion - I think the limit
> is ~1000 calls, although this can be changed (forgotten how at the moment,
>think
> it's somewhere in the sys module).
>
Yes, indeed you can set up that value to be higher, which I did in the new
version of the script pasted below.
> Looking at your code, it appears that 'accept_reject_monomer_pos' will recurse
> infinitely as the recursive call is made with the exact same parameters as the
> original.
No, it won't loop forever, since 'accept_reject_monomer_pos' in turns call
'random_on_sphere(dist)' that generates every time a new random position on a
sphere.
However, the problem now is that the modified version of the code pasted below
(where I simply set a very high maximum number of recursions) crashes for a
segmentation fault after a variable number of iterations and I have no idea
about where the segmentation fault arises from (never had one in Python).
Any suggestion is welcome.
Cheers
Lorenzo
>
> hope this helps,
> David
>
>
########################################################################
#! /usr/bin/env python
# from enthought.mayavi import mlab
import scipy as s
import numpy as n
import scipy.spatial as sp
import sys
sys.setrecursionlimit(1000000)
def accept_reject_monomer_pos(cluster_shifted, dist,epsi):
xyz=random_on_sphere(dist)
dist_list=s.zeros(0)
for i in s.arange(s.shape(cluster_shifted)[0]):
my_dist= sp.distance.euclidean(xyz,cluster_shifted[i,:])
# if (my_dist<=(2.+epsi)):
#i.e. excessive compenetration
if ((my_dist)<(2.-epsi)): \
return accept_reject_monomer_pos(cluster_shifted, dist,epsi)
dist_list=s.hstack((dist_list,my_dist))
sel=s.where(dist_list<=(2.+epsi))[0]
if (len(sel)==0): return accept_reject_monomer_pos(cluster_shifted,\
dist,epsi) #i.e. there are no contact points
cluster_shifted=s.vstack((cluster_shifted, xyz))
return cluster_shifted
def random_on_sphere(radius):
x12=s.random.uniform(-1.,1.,2)
if (s.sum(x12**2.)>=1.):return random_on_sphere(radius)
rvec=s.arange(3)*1.
rvec[0]=radius*2.*x12[0]*s.sqrt(1.-x12[0]**2.-x12[1]**2.)
rvec[1]=radius*2.*x12[1]*s.sqrt(1.-x12[0]**2.-x12[1]**2.)
rvec[2]=radius*(1.-2.*(x12[0]**2.+x12[1]**2.))
return rvec
# def new_dist_sq(N,df,kf):
# dsq=(N**2.)/(N-1.)*(N/kf)**(2./df)-N/(N-1.)-N*((N-1.)/kf)**(2./df)
# return dsq
def new_dist(N,df,kf):
dsq=(N**2.)/(N-1.)*(N/kf)**(2./df)-N/(N-1.)-N*((N-1.)/kf)**(2./df)
dsq=s.sqrt(dsq)
return dsq
def find_CM(cluster):
CM=s.mean(cluster, axis=0)
return CM
def relocate_cluster(cluster):
cluster_shift=find_CM(cluster)
cluster[:,0]=cluster[:,0]-cluster_shift[0]
cluster[:,1]=cluster[:,1]-cluster_shift[1]
cluster[:,2]=cluster[:,2]-cluster_shift[2]
return cluster
# NB: the cluster initially has N-1 monomers. N is the number of monomers
# after adding a new monomer.
N=3.
# a=1. and removed from the formula
kf=1.3
df= 1.2 # 1.8
epsi=0.05
test=0
N_iter=800
N=2
ini_cluster=s.arange(6).reshape((2,3))*1.
ini_cluster[0,0]=1.
ini_cluster[0,1]=0.
ini_cluster[0,2]=0.
ini_cluster[1,0]=-1.
ini_cluster[1,1]=0.
ini_cluster[1,2]=0.
cluster=ini_cluster
for i in s.arange(N_iter):
print "i is, ", i
cluster=relocate_cluster(cluster)
d_calc=new_dist(N,df,kf)
cluster=accept_reject_monomer_pos(cluster, d_calc,epsi)
N=N+1
n.savetxt("aggregate.dat", cluster)
More information about the SciPy-User
mailing list