[SciPy-User] scipy.linalg.solve()'s overwrite option does not work
braingateway
braingateway at gmail.com
Sat Nov 6 17:46:45 EDT 2010
Joe Kington :
>
> On Sat, Nov 6, 2010 at 12:13 PM, braingateway <braingateway at gmail.com
> <mailto:braingateway at gmail.com>> wrote:
>
> David Warde-Farley:
> > On 2010-11-05, at 9:21 PM, braingateway wrote:
> >
> >
> >> Hi everyone,
> >> I believe the overwrite option is used for reduce memory usage.
> But I
> >> did following test, and find out it does not work at all. Maybe I
> >> misunderstood the purpose of overwrite option. If anybody could
> explain
> >> this, I shall highly appreciate your help.
> >>
> >
> > First of all, this is a SciPy issue, so please don't crosspost
> to NumPy-discussion.
> >
> >
> >>>>> a=npy.random.randn(20,20)
> >>>>> x=npy.random.randn(20,4)
> >>>>> a=npy.matrix(a)
> >>>>> x=npy.matrix(x)
> >>>>> b=a*x
> >>>>> import scipy.linalg as sla
> >>>>> a0=npy.matrix(a)
> >>>>> a is a0
> >>>>>
> >> False
> >>
> >>>>> b0=npy.matrix(b)
> >>>>> b is b0
> >>>>>
> >> False
> >>
> >
> > You shouldn't use 'is' to compare arrays unless you mean to
> compare them by object identity. Use all(b == b0) to compare by value.
> >
> > David
> >
> >
> Thanks for reply, but I have to say u did not understand my post
> at all.
> I did this 'is' comparison on purpose, because I wanna know if the
> overwrite flag is work or not.
> See following example:
> >>> a=numpy.matrix([0,0,1])
> >>> a
> matrix([[0, 0, 1]])
> >>> a0=a
> >>> a0 is a
> True
>
>
> Just because two ndarray objects aren't the same doesn't mean that
> they don't share the same memory...
>
> Consider this:
> import numpy as np
> x = np.arange(10)
> y = x.T
> x is y # --> Yields False
> Nonetheless, x and y share the same data, and storing y doesn't double
> the amount of memory used, as it's effectively just a pointer to the
> same memory as x
>
> Instead of using "is", you should use "numpy.may_share_memory(x, y)"
Thanks a lot for pointing this out! I were struggling to figure out
whether the different objects share memory or not. And good to know
a0=numpy.matrix(a) actually did not share the memory.
>>> print 'a0 shares memory with a?', npy.may_share_memory(a,a0)
a0 shares memory with a? False
>>> print 'b0 shares memory with b?', npy.may_share_memory(b,b0)
b0 shares memory with b? False
I also heard that even may_share_memory is 'True', does not necessarily
mean they share any element. Maybe, is 'a0.base is a' usually more
suitable for this purpose?
Back to the original question: is there anyone actually saw the
overwrite_a or overwrite_b really showed its effect?
If you could show me a repeatable example, not only for
scipy.linalg.solve(), it can also be other functions, who provide this
option, such as eig(). If it does not show any advantage in memory
usage, I might still using numpy.linalg.
>
> This means a0 and a is actually point to a same object. Then a0 act
> similar to the C pointer of a.
> I compared a0/b0 and a/b by 'is' first to show I did create a new
> object
> from the original matrix, so the following (a0==a).all()
> comparison can
> actually prove the values inside the a and b were not overwritten.
>
> Sincerely,
> LittleBigBrain
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