[SciPy-User] scipy.interpolate.rbf sensitive to input noise ?

[denis]

On Feb 18, 4:48 pm, Robert Kern <robert.k... at gmail.com> wrote:
> On Thu, Feb 18, 2010 at 09:19, denis <denis-bz... at t-online.de> wrote:

> > Running rbf on 100 1d random.uniform input points
> > (after changing the linalg.solve in rbf.py to lstsq)
>
> Why would you do this? This does not magically turn Rbf interpolation
> into a smoothing approximation. Use the "smooth" keyword to specify a
> smoothing parameter.

Robert,
  i'm interpolating  y = np.sin(x) + np.random.normal( 0,  .1 ), not
random noise.
The idea was to look at gaussian vs thin-plate;
true, that 1d snippet doesn't say much,
but my 2d plots were so noisy that I went down to 1d.

Use "smooth" ? rbf.py just does
    self.A = self._function(r) - eye(self.N)*self.smooth
and you don't know A .

Bytheway (googling), http://www.farfieldtechnology.com/products/toolbox
...
have an O(N lnN) FastRBF TM in matlab, $

cheers
  -- denis