[SciPy-user] toimage

[Maik Trömel]

Hi Stefan,

works great! Thanks.

Greetings
Maik

Stefan van der Walt wrote:

>Hi Maik
>
>On Wed, Jun 07, 2006 at 11:42:08AM +0200, Maik Trömel wrote:
>  
>
>>i've got some problems creating a RGB-picture with "toimage".
>>I have createt an array with integer values betweeen 0 and 4095.
>>I tried with:
>>
>>i = scipy.misc.toimage(arr, high = 0, low = 255, cmax=4095, cmin=0, pal=3, mode='P')
>>    
>>
>
>'pal' is the image colourmap.  If you look at the toimage docstring,
>it says:
>
>    For 2-D arrays, if pal is a valid (N,3) byte-array giving the RGB values
>    (from 0 to 255) then mode='P', otherwise mode='L', unless mode is given
>    as 'F' or 'I' in which case a float and/or integer array is made
>
>For example, let's generate a square image that has a linear gradient:
>
>import numpy as N
>im = N.empty((100,100),dtype=N.Float)
>im[:] = N.linspace(0,4096,100)
>
>If you have matplotlib installed, you can view this using
>
>import pylab as P
>P.imshow(im,cmap=P.cm.gray)
>
>To convert the array im to a PIL image, you can now do
>
>I = scipy.misc.toimage(im,high=255,low=0,cmax=4095,cmin=0)
>
>and display it using
>
>I.show()
>
>Now, if we'd like to change the colourmap, we'll have to generate one.
>A colourmap is of shape (N,3), i.e. the RGB values for N indeces.  The
>following commands will generate a "cool" colourmap.
>
>map = N.empty((256,3),dtype=N.uint8)
>map[:,0] = N.arange(0,256,dtype=N.uint8)
>map[:,1] = map[:,0][::-1]
>map[:,2] = map[:,0] + map[:,1]
>
>We create the PIL image using
>
>I = scipy.misc.toimage(im,high=255,low=0,cmax=4095,cmin=0,pal=map,mode='P')
>
>after which we can display it using
>
>I.show()
>
>Regards
>Stéfan
>
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>  
>