[SciPy-user] ODE solver's in scipy
Nils Wagner
nwagner at mecha.uni-stuttgart.de
Mon Nov 4 07:51:19 EST 2002
Robert Kern schrieb:
>
> On Mon, Nov 04, 2002 at 12:34:36PM +0100, Nils Wagner wrote:
> > Hi,
> >
> > How can I solve the following ODE in scipy
> >
> > A(t,z) \dot{z} = f(z), z(0) = z_0
> >
> > where A is a real matrix depending on t and z;
> > \dot denotes derivative with respect to time t.
>
> from scipy import linalg, integrate
>
> def A(t,z):
> ...
>
> def f(z):
> ...
>
> def F(z, t):
> return linalg.solve(A(t,z), f(z))
>
> t = arange(0, 100, 0.1) # or whatever
> z0 = array([...])
>
> z = integrate.odeint(F, z0, t)
>
Thank you for your prompt reply. I have tried to transfer
your suggestion to my problem. However, I get some errors.
Traceback (most recent call last):
File "ivp.py", line 46, in F
return linalg.solve(A(P, Pl, M, K, t,z), f(P, M, K, z))
File "ivp.py", line 37, in A
A[0:n,0:n] = (1.0-t)*(K[0:n,0:n]-z[n]*M[0:n,0:n])+t*P[0:n,0:n]
TypeError: unsubscriptable object
odepack.error: Error occured while calling the Python function named F
So, what has to be amended in my program ivp.py ?
Nils
> --
> Robert Kern
> Ruddock House President
> kern at caltech.edu
>
> "In the fields of hell where the grass grows high
> Are the graves of dreams allowed to die."
> -- Richard Harter
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-------------- next part --------------
from scipy import *
from scipy import linalg, integrate
#
# A homotopy method for a nonlinear eigenvalue problem
#
# h = (1-t) [K x-lambda M x] + t P(lambda) x = 0
# 0.5*(x^T x -1) = 0
#
n = 3
#
# Linear eigenvalue problem : K x = lambda M x
#
K = array(([1.0,-1.0,0.0],
[-1.0,2.0,-1.0],
[0.0,-1.0,2.0]))
#
M = array(([2.0,1.0,0.0],
[1.0,4.0,1.0],
[0.0,1.0,4.0]))/6.0
#
w, vr = linalg.eig(K,M)
def P(t,z):
P = array(([z[n]/tan(z[n]),-z[n]/sin(z[n]),0.0],
[-z[n]/sin(z[n]),2.0*z[n]/tan(z[n]),-z[n]/sin(z[n])],
[0.0,-z[n]/sin(z[n]),2.0*z[n]/tan(z[n])]))
def Pl(t,z):
Pl = array(([cos(z[n])-z[n],z[n]*cos(z[n])-sin(z[n]),0.0],
[z[n]*cos(z[n])-sin(z[n]),2.0*(cos(z[n])-z[n]),z[n]*cos(z[n])-sin(z[n])],
[0.0,z[n]*cos(z[n])-sin(z[n]),2.0*(cos(z[n])-z[n])]))/sin(z[n])**2
def A(P, Pl, M, K, t,z):
A = zeros((n+1,n+1),Float)
A[0:n,0:n] = (1.0-t)*(K[0:n,0:n]-z[n]*M[0:n,0:n])+t*P[0:n,0:n]
A[n:0,n] = -(1-t)*dot(M,z[0:n])+t*dot(Pl,z[0:n])
A[n:0,n] = z[0:n]
def f(P, M, K, z):
f = zeros(n+1,Float)
f[0:n] = dot(K,z[0:n])-z[n]*dot(M,z[0:n])-dot(P,z[0:n])
def F(z, t):
return linalg.solve(A(P, Pl, M, K, t,z), f(P, M, K, z))
t = arange(0, 0.1, 0.05) # or whatever
z0=zeros(n+1,Float)
z0[0:n] = vr[:,0]
z0[n] = abs(w[0])
print z0
z = integrate.odeint(F, z0, t)
print 'Eigenvector',vr[:,0]
print 'Eigenvalue',w[0]
print z
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