neighbors contour length
Jaime Lopez Carvajal
jalopcar at gmail.com
Mon Oct 3 12:11:46 EDT 2016
Hi Juan,
Thank you for suggestion, I am going to take a look, but maybe I need a
different approach because the contour (list) of every object in image,
which were extracted after an image segmentation process.
So, I would like to know if there is a way to compare contours (comparing
lists) between objects to find shared coordinates, but I think this is not
possible because I have the inner contours of every object, so I will not
find any coordinates coincidence between pair of objects.
I hope this make my issue clearer.
Any other idea?
Thanks, Jaime
On Saturday, October 1, 2016 at 9:48:07 PM UTC-5, Juan Nunez-Iglesias wrote:
>
> Hi Jaime,
>
> Sorry, it seems your message got lost in our flooded inboxes...
>
> What does your source image look like? If the objects are segmented into
> different labels, that is, you have an image where all the pixels of object
> 1 have value 1, all those of object 2 have value 2, etc., then you can
> build a *region adjacency graph*, or RAG, with the right values to get what
> you need. This function in scikit-image master gets you the contour lengths
> between different objects, from which it should be easy to get the
> information you want:
>
>
> https://github.com/scikit-image/scikit-image/blob/master/skimage/future/graph/rag.py#L359
>
> By looking at the source code you might get even simpler code for your
> problem, because you just need the `count_matrix` sparse matrix. It should
> be super-fast to generate and compute the values you need.
>
> Juan.
>
> On Thu, Sep 15, 2016 at 7:29 AM, Jaime Lopez Carvajal <jalo... at gmail.com
> <javascript:>> wrote:
>
>> Hi,
>>
>> I would like to know if someone could help or suggest any idea how to do
>> this:
>>
>> First, I am trying to know how many neighbors (objects) one particular
>> object have using its contour.
>> Second, I need to extract the length of each shared contour with every
>> neighbor,
>> Third, calculate their respective percentage.
>>
>> The last step is the easiest, but I dont know how to get the first and
>> second steps.
>>
>> Example using attached image:
>>
>> Object of interest: red object
>> Neighbors: three neighbors with three shared contours (yellow, green and
>> blue).
>> Total length contour = lengh(yellow) + lengh(yellow) + lengh(yellow)
>>
>> Any suggestion how can I get this?
>>
>> Thanks in advance, Jaime
>>
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