[Pythonmac-SIG] Closing a blocked socket?

[Daniel Tartaglia]

The code below fails. Socket.accept blocks inside the thread and 
doesn't let go, even after the socket was closed. From the error 
presented, the socket never actually closes.

I realize that the below is a basic Java idiom but how do you do the 
same thing in Python? I ask here because when I asked on the newsgroup 
I got no response, so I started thinking it was a Mac only thing...

import unittest
import socket
import threading
import time

class SocketAcceptor ( threading.Thread ):
	def __init__( self, socket ):
		threading.Thread.__init__( self )
		self.socket = socket
		self.done = 0
		
	def run( self ):
		self.socket.bind( ( "", 3424 ) )
		self.socket.listen( 5 )
		try:
			child, ip = self.socket.accept()
		except:
			pass
		self.done = 1
		
class SocketTester ( unittest.TestCase ):
	def testClose( self ):
		for each in range( 4 ):
			ss = socket.socket()
			acceptor_thread = SocketAcceptor( ss )
			acceptor_thread.start()
			time.sleep( 1 )
			ss.close()
			time.sleep( 1 )
			self.assertEquals( acceptor_thread.done, 1 )
		
if __name__ == '__main__':
	unittest.main()