[python-win32] Windows services in python

[Dmitry Alekseenko]

win32service methods produces the same problem:

def Enable(self, serviceName, enable, autoStart=False):
    startType = None
    if not enable:
        startType = win32service.SERVICE_DISABLED
    elif autoStart:
        startType = win32service.SERVICE_AUTO_START
    else:
        startType = win32service.SERVICE_DEMAND_START

    scm = win32service.OpenSCManager(None, None,
                                     win32service.SC_MANAGER_ALL_ACCESS)
    svc = win32service.OpenService(scm, serviceName,
                                   win32service.SC_MANAGER_ALL_ACCESS)
    win32service.ChangeServiceConfig(svc, win32service.SERVICE_NO_CHANGE,
                                     startType,
                                     win32service.SERVICE_NO_CHANGE,
                                     None, None, 0, None, None, None, None)
    win32service.CloseServiceHandle(svc)

On 8/31/07, Tim Roberts <timr at probo.com> wrote:
>
> Dmitry Alekseenko wrote:
> > Hey guys,
> >
> > I've written the following function to enable/disable windows services:
> >
> > def Enable(self, serviceName, enable, autoStart=False):
> >     startType = None
> >     if not enable:
> >         startType = win32service.SERVICE_DISABLED
> >     elif autoStart:
> >         startType = win32service.SERVICE_AUTO_START
> >     else:
> >         startType = win32service.SERVICE_DEMAND_START
> >     win32serviceutil.ChangeServiceConfig(None, serviceName, startType)
> >
> > And it turns out that when I call Enable('W32Time', False) it corrupts
> > the "path to executable" property of the service. It replaces the path
> > to "C:\Python24\lib\site-packages\win32\PythonService.exe".
> >
> > What wrong am I doing?
>
> win32serviceutil.ChangeServiceConfig is a wrapper around the service
> management APIs, designed specifically for managing Python services.
> When you omit the exeName parameter, it assumes you want the generic
> Python service wrapper, and looks up the name.
>
> I suggest you skip the win32serviceutil wrapper altogether and call
> win32service.ChangeServiceConfig.  That is a much more direct wrapper
> around the Win32 API.  You will have to open the service manager
> yourself, but you can look at the source for win32serviceutil.py to see
> how to do that.
>
> --
> Tim Roberts, timr at probo.com
> Providenza & Boekelheide, Inc.
>
> _______________________________________________
> python-win32 mailing list
> python-win32 at python.org
> http://mail.python.org/mailman/listinfo/python-win32
>
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