Request for argmax(list) and argmin(list)

[Dan Stromberg]

How about this?:

python3 -c 'list_ = [1, 3, 5, 4, 2]; am = max((value, index) for index,
value in enumerate(list_)); print(am)'


On Wed, Sep 1, 2021 at 6:51 AM ABCCDE921 <atharvasakhala5445 at gmail.com>
wrote:

> Because that does 2 passes over the entire array when you only need one
> and there is no option to specify if you want the leftmost or rightmost
> element
>
>
> On Wednesday, September 1, 2021 at 12:02:29 PM UTC+5:30, Paul Bryan wrote:
> > Why not:
> >
> > >>> l = [1, 3, 5, 9, 2, 7]
> > >>> l.index(max(l))
> > 3
> > >>> l.index(min(l))
> > 0
> > On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote:
> > > I dont want to import numpy
> > >
> > > argmax(list)
> > > returns index of (left most) max element
> > >
> > > argmin(list)
> > > returns index of (left most) min element
> --
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>