Why are both locals() and globals() set?

[Peng Yu]

Hi, The following example shows that both locals() and globals() are
updated when x and f are defined. Shouldn't they be considered and
global variable and functions only? Why does it make sense to set
locals() as well? Thanks.

$ cat  ./main.py
#!/usr/bin/env python
# vim: set noexpandtab tabstop=2 shiftwidth=2 softtabstop=-1 fileencoding=utf-8:

d = dict()

d['l1'] = set(locals().keys())
d['g1'] = set(globals().keys())

x = 10
def f():
  pass

d['l2'] = set(locals().keys())
d['g2'] = set(globals().keys())

print d['l2'] - d['l1']
print d['g2'] - d['g1']

import os.path
d['l3'] = set(locals().keys())
d['g3'] = set(globals().keys())

print d['l3'] - d['l2']
print d['g3'] - d['g2']

from os import path
d['l4'] = set(locals().keys())
d['g4'] = set(globals().keys())

print d['l4'] - d['l3']
print d['g4'] - d['g3']

$  ./main.py
set(['x', 'f'])
set(['x', 'f'])
set(['os'])
set(['os'])
set(['path'])
set(['path'])


-- 
Regards,
Peng