Detect file is locked - windows
Aahz
aahz at pythoncraft.com
Thu Nov 15 11:01:45 EST 2012
In article <mailman.3676.1352887368.27098.python-list at python.org>,
Tim Golden <mail at timgolden.me.uk> wrote:
>On 14/11/2012 00:33, Ali Akhavan wrote:
>>
>> I am trying to open a file in 'w' mode open('file', 'wb'). open()
>> will throw with IOError with errno 13 if the file is locked by
>> another application or if user does not have permission to open/write
>> to the file.
>>
>> How can I distinguish these two cases ? Namely, if some application
>> has the file open or not.
>
>Can I ask what you expect to do differently in each of those cases? In
>other words, if you can't access the file, you can't access it. (Not to
>dismiss your question; I just wonder how you're going to handle the
>different cases)
Real-life use case for user-requested operation: if no permission, skip
the file "permanently" (until it changes, at least); if locked, place in
retry loop.
And in response to your other post, you absolutely want to use
CreateFileW()... ;-)
--
Aahz (aahz at pythoncraft.com) <*> http://www.pythoncraft.com/
"LL YR VWL R BLNG T S" -- www.nancybuttons.com
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