subtract dates with time module
John Machin
sjmachin at lexicon.net
Thu Mar 27 06:56:29 EDT 2008
barronmo wrote:
> I'm trying to get the difference in dates using the time module rather
> than datetime because I need to use strptime() to convert a date and
> then find out how many weeks and days until that date.
datetime.datetime.strptime was introduced in Python 2.5; what version
are you using?
If you really want to get to datetime, here's a quick bridge:
>>> import time, datetime
>>> def mystrptime(astr, format):
... return datetime.datetime(*time.strptime(astr, format)[:6])
...
>>> mystrptime('2008-03-31', '%Y-%m-%d')
datetime.datetime(2008, 3, 31, 0, 0)
> I'm a beginner
> so any help would be appreciated. Here is the code:
>
> def OBweeks(ptID):
> qry = 'SELECT short_des FROM problems WHERE patient_ID = %s;' %
> (ptID)
> results = EMR_utilities.getAllData(qry)
> for items in results:
> r = re.search('\d\d\d\d-\d\d-\d\d', items)
> if r:
> d = time.strptime(r.group(), "%Y-%m-%d') -
You have " at the start and ' at the end of what's supposed to be a
string constant. That's a syntax error; it won't run. Please don't serve
up what you thought you might have run -- use copy/paste.
In this particular case, you can just use time.mktime to convert a time
tuple into days since the epoch.
# untested
days = time.mktime(time.strptime(r.group(), "%Y-%m-%d")) -
int(time.mktime(time.localtime()))
weeks, days = divmod(days, 7)
> time.localtime()
> weeks, days = divmod(d.days, 7)
> return '%s %s/7 weeks' % (weeks, days)
>
> This isn't working. I'm getting "unsupported operand type for -:
> 'time.struct_time' and 'time.struct_time" error.
It *is* working. That is the correct result of the code that you
executed. There is is nothing in the time docs to suggest that
attempting to subtract time tuples produces anything useful.
HTH,
John
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