function that accepts any amount of arguments?

[Bruno Desthuilliers]

Paul McNett a écrit :
> 
> def avg(*args):
>   return sum(args) / len(args)
> 
> There are some dangers (at least two glaring ones)  with this code,
> though, which I leave as an exercise for the reader.

try:
   avg("toto", 42)
except TypeError, e:
   print "this is the first one : %s" % e
try:
   avg()
except  ZeroDivisionError, e:
   print "this is the second : %s" % e

As far as I'm concerned, I would not handle the first one in the avg 
function - just document that avg expects numeric args.

Not quite sure what's the best thing to do in the second case - raise a 
ValueError if args is empty, or silently return 0.0 - but I'd tend to 
choose the first solution (Python's Zen, verses 9-11).