Dynamic File Name Open()
Robert Rawlins - Think Blue
robert.rawlins at thinkbluemedia.co.uk
Wed May 2 01:43:31 EDT 2007
Chaps,
I'm trying to open a file using open() but the name of the file is created
dynamically as a variable, but also has part of a static path. For instance,
the file may be called 'dave' and will always be in '/my/files/here/'.
Now I've tried a few combinations of getting this to work, such as.
Path = '/my/files/here/%s' % (name)
Open(Path, 'r')
But that does work, can anyone enlighten me on the best way to do this?
Thanks,
Rob
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