Escaping the semicolon?
Sergio Correia
sergio.correia at gmail.com
Tue Dec 4 11:01:40 EST 2007
On Dec 4, 2007 10:40 AM, Nick <nickjbyrne at gmail.com> wrote:
> Is this expected behavior?
>
> >>> s = '123;abc'
> >>> s.replace(';', '\;')
> '123\\;abc'
>
Everything is Ok. It's still a single backslash. Try:
>>> print s.replace(';', '\;')
Or
>>> x = s.replace(';', '\;')
>>> print x
Best,
Sergio
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