Do I need a nested lambda to do this?

[Bill Mill]

On 4/25/05, R. C. James Harlow <james at wrong.nu> wrote:
> On Tuesday 26 April 2005 00:34, raoul wrote:
> > I can't figure this one out. Trying to be unnecessarily functional I
> > suspect.
> 
> With list comprehensions:
> 
> Python 2.3.4 (#1, Mar 26 2005, 20:54:10)
> [GCC 3.3.4 20040623 (Gentoo Linux 3.3.4-r1, ssp-3.3.2-2, pie-8.7.6)] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
> >>> vals = [1.000,2.344,4.2342]
> >>> tabs = [((0,1),(0,3),(0,4)),
> ...        ((2,2),(3,0),(3,9)),
> ...        ((3,4),(6,3),(7,1))]
> >>> [(tuple([(vals[index],subtab[1]) for subtab in tab])) for index,tab in
> enumerate(tabs)]
> [((1.0, 1), (1.0, 3), (1.0, 4)), ((2.3439999999999999, 2),
> (2.3439999999999999, 0), (2.3439999999999999, 9)), ((4.2342000000000004, 4),
> (4.2342000000000004, 3), (4.2342000000000004, 1))]

Slightly nicer, I think:

>>> vals
[1.0, 2.3439999999999999, 4.2342000000000004]
>>> tabs
[((0, 1), (0, 3), (0, 4)), ((2, 2), (3, 0), (3, 9)), ((3, 4), (6, 3), (7, 1))]
>>> [tuple([(v, t[1]) for t in tab]) for v, tab in zip(vals, tabs)]
[((1.0, 1), (1.0, 3), (1.0, 4)), 
((2.3439999999999999, 2), (2.3439999999999999, 0), 
  (2.3439999999999999, 9)), 
((4.2342000000000004, 4), (4.2342000000000004, 3),
  (4.2342000000000004, 1))]

Peace
Bill Mill
bill.mill at gmail.com

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