Best way to get ip address

[Darren Kirby]

quoth the John Lenton:
> this is more convoluted, and depends on a third party, but I find it's
> the most reliable way to find out what you seem to be wanting:
>
>     re.findall('[0-9.]+',
>                urllib.urlopen('http://checkip.dyndns.org/').read())[-1]
>
> there are several apps out there that depend on checkip.dyndns.org,
> and it's a published service, so it shouldn't be changing too often.
>
> HTH.

This is funny. I just spent the last hour putting together this:

    def getIpAddress():
 command = "lynx -dump http://whatismyip.com | awk '/Your/ {print $4}'"
 x = commands.getstatusoutput(command)
 if x[0] != 0:
  ip = '127.0.0.1'
 else:
  ip = x[1]
 return ip

Same principle, but relies on a third party and two system commands. I think I 
will re-write it to use urllib as in your example.

Thanks everyone for the help...I think I've got it now.

-d

-- 
Part of the problem since 1976
http://badcomputer.no-ip.com
Get my public key from 
http://keyserver.linux.it/pks/lookup?op=index&search=bulliver
"...the number of UNIX installations has grown to 10, with more expected..."
- Dennis Ritchie and Ken Thompson, June 1972 
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