list.pop and print doing funny things

[Larry Bates]

Whenever you pop from the list it is destructive
and the result is returned, which means it will
be echoed in the interpreter.

I think what you meant was:

for x in range(len(l)):
    value=l.pop(0) # From beginning
    print value
    print l

    # or

    value=l.pop()  # From end
    print value     print l

or

while l:
    print l.pop(0) # From beginning
    print l

    # or

    print l.pop() # From end
    print l


The indexing, etc. wasn't required.

Larry Bates


"Gordon Williams" <g_will at cyberus.ca> wrote in message 
news:mailman.3669.1095791640.5135.python-list at python.org...
> An easy question....
>
> Why do I get the x printed twice in the sample below? It is like print x 
> is
> being executed twice in each loop.
>
>
>>>> l = [1,2,3,4]
>>>> for x in l[:]:
> ...  print x
> ...  l.pop(l.index(x))
> ...  print l
> ...
> 1
> 1
> [2, 3, 4]
> 2
> 2
> [3, 4]
> 3
> 3
> [4]
> 4
> 4
> []
>>>>
>
> Regards,
>
> Gordon Williams
>