splitString output as argument to string format fails?
Peter Otten
__peter__ at web.de
Wed Mar 24 13:44:55 EST 2004
U-CDK_CHARLES\Charles wrote:
> But when I attempt something like:
>
> f = '%s %s %s' % string.split(eachLine, ',')
>
> I get:
>
> TypeError: not enough arguments for format string
>
> How do I convert the output of string.split into something the format
> operator is happy with? I'm looking for an "oh well of COURSE" thing,
> rather than looping over the output list and creating a tuple, assuming
> one exists.
The % operator is a bit picky about the sequence type - it wants a tuple:
>>> "%sx%s" % "a,b".split(",")
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: not enough arguments for format string
>>> "%sx%s" % tuple("a,b".split(","))
'axb'
Peter
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