How do I get info on an exception ?
Frank
Frank at home
Fri Jul 18 02:33:52 EDT 2003
Using Python 2.2.2,
I want to catch all exceptions from "socket.gethostbyaddr(ip)"
>From IDLE, I can generate:
>>> socket.gethostbyaddr('1.2')
Traceback (most recent call last):
File "<pyshell#28>", line 1, in ?
socket.gethostbyaddr('1.2')
herror: (11004, 'host not found') <=== what I want when I catch
When I run this code:
try:
hostname, aliases, hostip = socket.gethostbyaddr(ip)
return (hostip, hostname)
except:
print sys.exc_info()
print sys.exc_type
return
The "print sys.exc_info()" gives-
(<class socket.herror at 0x00AE7AC0>,
<socket.herror instance at 0x00C725C0>,
<traceback object at 0x00C73920>)
And the "print sys.exc_type" gives-
socket.herror
How do I get the "(11004, 'host not found')" part?
More importantly, where is the answer documented that I should
have looked?
Frank
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