How to get parent method as a function object?

[Chris Liechti]

David Eppstein <eppstein at ics.uci.edu> wrote in news:eppstein-
D8CBA2.13575911122002 at news.service.uci.edu:
> So my question is, suppose you don't want to call a shadowed method from 
> a parent class, instead you want to create a first-arg-instantiated 
> function object like you would get from self.foo?
...
> Or some other way of accessing 
> this pre-instantiation machinery outside of a class?

>>> class A(object):
... 	def m(self): print "A"
... 	
>>> class B(A):
... 	def m(self): print "B"
... 	
>>> b=B()
>>> super(B, b).m
<bound method m.m of <__main__.B object at 0x0117BB18>>
>>> super(B, b).m()
A
>>> b.m()
B

but only for new style classes.

chris

-- 
Chris <cliechti at gmx.net>