[1, 2] in [1, 2, 3] returns 0?
Sandy Norton
sandskyfly at hotmail.com
Sat Aug 25 14:27:06 EDT 2001
Please excuse me if this is a dumb comment that has been made before.
Recently, I was rather surprised by the following behavior:
Python 2.1.1 (#20, Jul 26 2001, 11:38:51) [MSC 32 bit (Intel)] on
win32
Type "copyright", "credits" or "license" for more information.
>>> lst = [1,2,3]
>>> sublst = [1,2]
>>> sublst in lst
0
I am sure there's a good reason why it would be considered unpythonic
for the above to return 1... I just can't get my puny brain to figure
it out right now.
I guess a function such as issublist(sublst, lst) would be more
appropriate:
>>> def issublist(sublst, lst):
for item in sublst:
if item not in lst: return 0
return 1
>>> issublist([1,2], [1,2,3])
1
>>> issublist([1,4], [1,2,3])
0
regards,
Sandy
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