Nth digit of PI

[Roy Smith]

Randall Hopper <aa8vb at yahoo.com> wrote:
>  Pi^2/8 = sum(n=1..inf, 1/(2n-1)^2)

Interesting, I've never seen that one before.

It's not a very efficient way to compute pi (I know, that's not what you were 
trying to do).  A little experimentation shows that 1000 terms only gets you 4 
significant digits correct, and 10,000 terms still only had 5!

-- 
Roy Smith <roy at popmail.med.nyu.edu>
New York University School of Medicine