Operators for matrix: current choices (Was Matlab vs Python ...)

[Huaiyu Zhu]

On Wed, 19 Jul 2000 21:01:22 +0100, Gareth McCaughan <gjm11 at g.local> wrote:

>You can do A\B in O(n^2) time? That's news to me. In fact,
>I don't believe you.

Oh-oh, (blush) The ratio between A.inv*B and A\B is more like (n+m)/(n/6+m),
or something similar.  The the factor is larger for smaller m, but it's
bounded and not going up like n.

Huaiyu