Closing a file

[j vickroy]

Hello Duncan,

Unless I'm missing something here, the file will not be closed by this method
(function) if n <=900000.  If the file is not closed elsewhere in the code, it
will only be closed (by Python) when the interpreter exits as part of its
cleanup.

Duncan Smith wrote:

> I am attempting to write data to a file so I can export it to another
> application after running a simulated annealing algorithm.  (self.cost == 0
> on the first iteration only.)  The relevant code is below.  The file seems
> to be created and written to O.K., bit it's not closed and I can't access
> 'simresults.txt' without shutting down Python.  I've checked the FAQ etc.
> but I'm no computer scientist and I can't figure out where I'm going wrong.
> Thanks in advance for any help.
>
> from Numeric import *
> from Set import *
> from RandomArray import *
> import sys
>
>     def acceptsim(self, cost, n):
>         t = 10000.0 / n
>         if self.cost == 0:
>             outputfile = open('simresults.txt', 'w')
>             sys.stdout = outputfile
>             self.cost = DJT.totalcost(self)
>             self.low_cost = self.cost
>             self.low_ordering = self.ordering[:]
>         if n > 900000:
>             outputfile.close()
>             return 'stop'
>         if cost > 0:
>             p = exp ((-1 / t) * (float(cost) / self.cost))
>             if random() > p:
>                 print self.cost
>                 return 0
>             else:
>                 self.cost = self.cost + cost
>                 print self.cost
>                 return 1
>         else:
>             self.cost = self.cost + cost
>             if self.cost < self.low_cost:
>                 self.low_cost = self.cost
>                 self.low_ordering = self.ordering[:]
>             print self.cost
>             return 1