changing umask from ftplib

[Steffen Ries]

j vickroy <jvickroy at sec.noaa.gov> writes:

> I am having difficulty using the sendcmd() method of the FTP class in
> the ftplib module.  The ftpmirror.py example that comes with the Python
> 1.5.2 distribution does not appear to cover this, and I guess I don't
> understand the online documentation either.  In any event, this is an
> example:
> 
> >>>
> >>> import ftplib
> >>> ftp = ftplib .FTP ('the_machine','the_user','the_password')
> >>> result = ftp .sendcmd ('umask 113')
> Traceback (innermost last):
>   File "<stdin>", line 1, in ?
>   File "/local/Python-1.5.2_threads_work/Lib/ftplib.py", line 228, in
> sendcmd
>     return self.getresp()
>   File "/local/Python-1.5.2_threads_work/Lib/ftplib.py", line 201, in
> getresp
>     raise error_perm, resp
> ftplib.error_perm: 500 'UMASK 113': command not understood.
> >>>
> 
> However, I can issue the command from an ftp session as follows:
> 
> 230 User the_user logged in.
> Remote system type is UNIX.
> Using binary mode to transfer files.
> ftp> umask 113
> 200 UMASK set to 113 (was 022)
> 
> What am I doing wrong?

The FTP client translates the commands you enter into commands the FTP
server understands. 'UMASK' is not a supported command, but is
available on unix hosts through the 'SITE' command. -> try:

  ftp.sendcmd('SITE UMASK 113')

(`man ftpd' may give you an insight)

/steffen
-- 
steffen.ries at sympatico.ca	<> Gravity is a myth -- the Earth sucks!