[Python-ideas] Hexadecimal floating literals

[Guido van Rossum]

On Thu, Sep 21, 2017 at 8:30 PM, David Mertz <mertz at gnosis.cx> wrote:

> Simply because the edge cases for working with e.g. '0xC.68p+2' in a
> hypothetical future Python are less obvious and less simple to demonstrate,
> I feel like learners will be tempted to think that using this base-2/16
> representation saves them all their approximation issues and their need
> still to use isclose() or friends.
>

Show them 1/49*49, and explain why for i < 49, (1/i)*i equals 1 (lucky
rounding).

-- 
--Guido van Rossum (python.org/~guido)
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