[Python-ideas] operator.call / operator.__call__

[Jonas Wielicki]

On 30.10.2014 10:03, Andrew Barnert wrote:
> On Oct 30, 2014, at 1:23, Jonas Wielicki <j.wielicki at sotecware.net> wrote:
> 
>> (only referring to the second use case here)
>>
>> On 30.10.2014 09:07, Antony Lee wrote:
>>> [snip]
>>>        self.any_callable_signal.connect(lambda f: f()) # <- operator.call
>>> seems to express this better.
>>>    def call_in_gui_thread(self, func):
>>>        self.any_callable_signal.emit(func)
>>
>> How is that different from directly passing f? Or use functools.partial
>> in case you need to pass additional, fixed arguments to f.
> 
> He's passing a function that takes any function f and calls it. That's not the same as passing any particular function.
> 
> Maybe it's more obvious if you compare:
> 
>     lambda f: f()
>     lambda: f()
> 

Right, I missed that, sorry for the noise.

regards,
jwi