[Python-ideas] Optional keepsep argument in str.split()

[Marco Buttu]

On 08/28/2013 09:36 PM, Masklinn wrote:
> and the "keeping" split can be handled via findall:
>
>>>> >>>re.findall(r'([^n]+(?:n|$))', "python3")
> ['python', '3']

Of course, but this is not built-in and not obvious. Furthermore, a 
regex is not so trivial as the built-in solution, as
you can see:

 >>> re.findall(r'([^n]+(?:n|$))', "pythonn3")
['python', '3']
 >>> 'pythonn3'.split(sep='n', keepsep=True)
['python', 'n', '3']

Regards,

-- 
Marco Buttu

INAF Osservatorio Astronomico di Cagliari
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