[Python-Dev] Why does Signature.from_function() have to check the type of its argument?
Benjamin Peterson
benjamin at python.org
Fri Feb 8 16:06:09 CET 2013
2013/2/8 Stefan Behnel <stefan_ml at behnel.de>:
> Hi,
>
> I'm wondering about the purpose of this code in
> inspect.Signature.from_function():
>
> """
> if not isinstance(func, types.FunctionType):
> raise TypeError('{!r} is not a Python function'.format(func))
> """
>
> Is there any reason why this method would have to explicitly check the type
> of its argument? Why can't it just accept any object that quacks like a
> function?
The signature() function checks for types.FunctionType in order to
call Signature.from_function(). How would you reimplement that?
--
Regards,
Benjamin
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