[Python-Dev] __setcall__

[Bj Raz]

I'll look into SAGE, I am still curious if there is, a way, to write this in native python, cause I'm currently plotting in Autodesk Maya, and using Python. 

Sent from my iPhone

On Oct 24, 2010, at 12:51 PM, Benjamin Peterson <benjamin at python.org> wrote:

> 2010/10/24 Bj Raz <whitequill.bj at gmail.com>:
>> I was looking for a way to set a function being equal to another function:
>> q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer);
>> I was hoping to use something like this:
>> (q).__setcall__.(m+1) = (q).__setcall__.(m)+ ((-1)^m) * exp(lnanswer);
>> As a work around.
>> But I have not found the `__setcall__' built in being there.
>> 
>> Here is the code block I'm working with:
>> 
>> indvar = 200;
>> q = 0;
>> lnanswer = 0;
>> for m = 1:150
>>   lnanswer = (3 * m) * log(indvar) - log(factorial(3 * m))  ;
>> q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer);
>> end
>> lnanswer
>> q
>> 
>> Any help would be appreciated.
> 
> Please see python-list. This list is for the development of python.
> 
> The SAGE math package can do something like this.
> 
> 
> 
> -- 
> Regards,
> Benjamin