[Python-checkins] [3.11] Python documents state elsewhere that a comma is not an operator (GH-98736) (#98757)

[ambv]

https://github.com/python/cpython/commit/434943e0b461f5d4c8e772a4117bbf99e99d1fa3
commit: 434943e0b461f5d4c8e772a4117bbf99e99d1fa3
branch: 3.11
author: Miss Islington (bot) <31488909+miss-islington at users.noreply.github.com>
committer: ambv <lukasz at langa.pl>
date: 2022-10-28T12:15:34+02:00
summary:

[3.11] Python documents state elsewhere that a comma is not an operator (GH-98736) (#98757)

Python documents state elsewhere that a comma is not an operator, so calling it an operator here is confusing. See https://docs.python.org/3/reference/lexical_analysis.htmlGH-operators and https://docs.python.org/3/faq/programming.htmlGH-id22.
(cherry picked from commit d578aaea6257458c199328100cbb5af64c6a043e)

Co-authored-by: Gerardwx <Gerardwx at users.noreply.github.com>

files:
M Doc/reference/expressions.rst

diff --git a/Doc/reference/expressions.rst b/Doc/reference/expressions.rst
index cc969752d5d7..0cdf91e75b34 100644
--- a/Doc/reference/expressions.rst
+++ b/Doc/reference/expressions.rst
@@ -154,7 +154,7 @@ tuple may or may not yield the same object).
    single: , (comma)
 
 Note that tuples are not formed by the parentheses, but rather by use of the
-comma operator.  The exception is the empty tuple, for which parentheses *are*
+comma.  The exception is the empty tuple, for which parentheses *are*
 required --- allowing unparenthesized "nothing" in expressions would cause
 ambiguities and allow common typos to pass uncaught.