[Python-checkins] test_thread uses support.sleeping_retry() (#93849)

[vstinner]

https://github.com/python/cpython/commit/bddbd80cff950b16712ae9e72eeba2a0f26c65e0
commit: bddbd80cff950b16712ae9e72eeba2a0f26c65e0
branch: main
author: Victor Stinner <vstinner at python.org>
committer: vstinner <vstinner at python.org>
date: 2022-06-15T13:52:13+02:00
summary:

test_thread uses support.sleeping_retry() (#93849)

test_thread.test_count() now fails if it takes longer than
LONG_TIMEOUT seconds.

files:
M Lib/test/test_thread.py

diff --git a/Lib/test/test_thread.py b/Lib/test/test_thread.py
index ed527e7164fd0..2ae5e9ccb4408 100644
--- a/Lib/test/test_thread.py
+++ b/Lib/test/test_thread.py
@@ -13,7 +13,6 @@
 
 NUMTASKS = 10
 NUMTRIPS = 3
-POLL_SLEEP = 0.010 # seconds = 10 ms
 
 _print_mutex = thread.allocate_lock()
 
@@ -121,19 +120,24 @@ def task():
 
         with threading_helper.wait_threads_exit():
             thread.start_new_thread(task, ())
-            while not started:
-                time.sleep(POLL_SLEEP)
+            for _ in support.sleeping_retry(support.LONG_TIMEOUT):
+                if started:
+                    break
             self.assertEqual(thread._count(), orig + 1)
+
             # Allow the task to finish.
             mut.release()
+
             # The only reliable way to be sure that the thread ended from the
-            # interpreter's point of view is to wait for the function object to be
-            # destroyed.
+            # interpreter's point of view is to wait for the function object to
+            # be destroyed.
             done = []
             wr = weakref.ref(task, lambda _: done.append(None))
             del task
-            while not done:
-                time.sleep(POLL_SLEEP)
+
+            for _ in support.sleeping_retry(support.LONG_TIMEOUT):
+                if done:
+                    break
                 support.gc_collect()  # For PyPy or other GCs.
             self.assertEqual(thread._count(), orig)