[Python-checkins] bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443)
Mariatta
webhook-mailer at python.org
Fri Nov 24 23:56:03 EST 2017
https://github.com/python/cpython/commit/610e5afdcbe3eca906ef32f4e0364e20e1b1ad23
commit: 610e5afdcbe3eca906ef32f4e0364e20e1b1ad23
branch: master
author: Mandeep Bhutani <mandeep at users.noreply.github.com>
committer: Mariatta <Mariatta at users.noreply.github.com>
date: 2017-11-24T20:56:00-08:00
summary:
bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443)
The provided code example was supposed to find repeated words, however it returned false results.
files:
M Doc/howto/regex.rst
diff --git a/Doc/howto/regex.rst b/Doc/howto/regex.rst
index e8466ee5423..fa8c6939408 100644
--- a/Doc/howto/regex.rst
+++ b/Doc/howto/regex.rst
@@ -844,7 +844,7 @@ backreferences in a RE.
For example, the following RE detects doubled words in a string. ::
- >>> p = re.compile(r'(\b\w+)\s+\1')
+ >>> p = re.compile(r'\b(\w+)\s+\1\b')
>>> p.search('Paris in the the spring').group()
'the the'
@@ -943,9 +943,9 @@ number of the group. There's naturally a variant that uses the group name
instead of the number. This is another Python extension: ``(?P=name)`` indicates
that the contents of the group called *name* should again be matched at the
current point. The regular expression for finding doubled words,
-``(\b\w+)\s+\1`` can also be written as ``(?P<word>\b\w+)\s+(?P=word)``::
+``\b(\w+)\s+\1\b`` can also be written as ``\b(?P<word>\w+)\s+(?P=word)\b``::
- >>> p = re.compile(r'(?P<word>\b\w+)\s+(?P=word)')
+ >>> p = re.compile(r'\b(?P<word>\w+)\s+(?P=word)\b')
>>> p.search('Paris in the the spring').group()
'the the'
More information about the Python-checkins
mailing list